Skip any url query segment that doesn't contain an "=", so

that a query like "?&ipr_id=657" can be parsed.
 - Legacy-Id: 415

Author: fenner

ietf/tests.py

@@ -57,7 +57,7 @@ def get_patterns(module):
 def split_url(url):
     if "?" in url:
         url, args = url.split("?", 1)
-        args = dict([ arg.split("=", 1) for arg in args.split("&") ])
+        args = dict([ arg.split("=", 1) for arg in args.split("&") if "=" in arg ])
     else:
         args = {}
     return url, args